2x^2+10x/25=0

Solution for 2x^2+10x/25=0 equation:

2x^2+10x/25=0

We multiply all the terms by the denominator


2x^2*25+10x=0

Wy multiply elements

50x^2+10x=0

a = 50; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·50·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*50}=\frac{-20}{100}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*50}=\frac{0}{100}
=0
$